Math, asked by samirasamira66, 26 days ago

please help me please ​

Attachments:

Answers

Answered by UserUnknown57
0

Answer:

step by step explanation:

( ii )

\Large{\mathsf{ \Rightarrow 2x^2 -7x +5 }}

\Large{\mathsf{ \Rightarrow 2x^2 -5x-2x+5 }}

\Large{\mathsf{ \Rightarrow x(2x-5)-1(2x-5) }}

\Large{\mathsf{ \Rightarrow (x-1)(2x-5) }}

\Large{\mathsf{ x =1 \:or \:  x = \frac{5}{2} }}

\Large{\mathsf{ \Rightarrow 1+ \frac{5}{2} }}

\Large{\mathsf{ \Rightarrow \frac{1}{1}+ \frac{5}{2} }}

\huge{\mathsf{ \Rightarrow \frac{(2+5)}{2}}}

\huge{\mathsf{ \Rightarrow \frac{7}{2}}}

( iii )

\Large{\mathsf{ \Rightarrow 2x^2 -8}}

\huge{\mathsf{x^2 \Rightarrow \frac{8}{2}}}

\Large{\mathsf{x^2 \Rightarrow 4}}

\Large{\mathsf{x \Rightarrow \sqrt{4}}}

\Large{\mathsf{x \Rightarrow 2\:or\: -2}}

\Large{\mathsf{ \Rightarrow 2 + (-2)}}

\Large{\mathsf{ \Rightarrow 2  -2}}

\Large{\mathsf{ \Rightarrow 0}}

Similar questions