Math, asked by kritika94886, 11 months ago

please help me !
please! ​

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Answered by AnuShakya
0

Hope my answer helped you

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Answered by Anonymous
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\tt{ \frac{3}{4} (7x - 1) - (2x -  \frac{1 - x}{2}) = x +  \frac{3}{2}}

 \tt{\frac{21x}{4} -  \frac{3}{4} - ( \frac{2x \times 2}{1 \times 2}  -  \frac{1 - x}{2}) = x +  \frac{3}{2}}

\tt{ \frac{21x}{4} -  \frac{3}{4} - ( \frac{4x}{2}   -  \frac{1 - x}{2}) = x +  \frac{3}{2}}

\tt{ \frac{21x}{4} -  \frac{3}{4} - ( \frac{4x - (1 - x)}{2}) = x +  \frac{3}{2}}

\tt{\frac{21x}{4} -  \frac{3}{4} - ( \frac{4x - 1 + x}{2}) = x +  \frac{3}{2}}

 \tt{\frac{21x}{4} -  \frac{3}{4} -  (\frac{5x - 1}{2}) = x +  \frac{3}{2}}

\tt{ \frac{21x}{4}  - ( \frac{5x - 1}{2}) - x =  \frac{3}{2} +  \frac{3}{4}}

\tt{ \frac{21x}{4}  -  \frac{(5x - 1)2}{2 \times 2}  -  \frac{x \times 4}{1 \times 4}  =  \frac{3(2)+3}{4}}

 \tt{\frac{21x}{4}  -  \frac{10x - 2}{4} -  \frac{4x}{4}   =  \frac{6+3}{4} }

\tt{ \frac{21x - (10x - 2) - (4x)}{4} =  \frac{9}{4}}

\tt{ \frac{21x - 10x + 2 - 4x}{4} =  \frac{9}{4} }

\tt{ \frac{21x - 14x + 2}{4} =  \frac{9}{4}}

\tt{\frac{7x + 2}{4} =  \frac{9}{4}}

4 and 4 will be cancelled, as denominators are equal on both the sides

\tt{7x + 2 = 9}

\tt{7x = 9 - 2}

\tt{7x = 7}

\tt{x =  \frac{7}{7}}

\tt{x =  1}

Extra info :

1)Equation : An open sentence which contains who is equal to (=) sign is called an equation.

e.g.x + 9 = 5

x + y + z = 16

2) Open sentence:A sentence for which we cannot decide whether it is true or false is called an open sentence.

R

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