Question

please help me !
please! ​

Answer 1

Hope my answer helped you

Answer 2

$\tt{ \frac{3}{4} (7x - 1) - (2x - \frac{1 - x}{2}) = x + \frac{3}{2}}$

$\tt{\frac{21x}{4} - \frac{3}{4} - ( \frac{2x \times 2}{1 \times 2} - \frac{1 - x}{2}) = x + \frac{3}{2}}$

$\tt{ \frac{21x}{4} - \frac{3}{4} - ( \frac{4x}{2} - \frac{1 - x}{2}) = x + \frac{3}{2}}$

$\tt{ \frac{21x}{4} - \frac{3}{4} - ( \frac{4x - (1 - x)}{2}) = x + \frac{3}{2}}$

$\tt{\frac{21x}{4} - \frac{3}{4} - ( \frac{4x - 1 + x}{2}) = x + \frac{3}{2}}$

$\tt{\frac{21x}{4} - \frac{3}{4} - (\frac{5x - 1}{2}) = x + \frac{3}{2}}$

$\tt{ \frac{21x}{4} - ( \frac{5x - 1}{2}) - x = \frac{3}{2} + \frac{3}{4}}$

$\tt{ \frac{21x}{4} - \frac{(5x - 1)2}{2 \times 2} - \frac{x \times 4}{1 \times 4} = \frac{3(2)+3}{4}}$

$\tt{\frac{21x}{4} - \frac{10x - 2}{4} - \frac{4x}{4} = \frac{6+3}{4} }$

$\tt{ \frac{21x - (10x - 2) - (4x)}{4} = \frac{9}{4}}$

$\tt{ \frac{21x - 10x + 2 - 4x}{4} = \frac{9}{4} }$

$\tt{ \frac{21x - 14x + 2}{4} = \frac{9}{4}}$

$\tt{\frac{7x + 2}{4} = \frac{9}{4}}$

4 and 4 will be cancelled, as denominators are equal on both the sides

$\tt{7x + 2 = 9}$

$\tt{7x = 9 - 2}$

$\tt{7x = 7}$

$\tt{x = \frac{7}{7}}$

$\tt{x = 1}$

Extra info :

1)Equation : An open sentence which contains who is equal to (=) sign is called an equation.

e.g.x + 9 = 5

x + y + z = 16

2) Open sentence:A sentence for which we cannot decide whether it is true or false is called an open sentence.

R