Question

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Answer 1

Answer:

Area of triangle = 1/2 × base × height

Height of triangle = 12cm

Base = 12cm

Therefore, Area = 1/2 × 12 × 12

= 1/2 × 144

= 72cm^2

In order to find area of sector AEF , we need to add area of 'ii' and subtract the area of 'i' to the area of the triangle .

Therefore, Area of sector = 72 + Area of 'ii' - Area of 'i'

Since both the areas of 'ii' and 'i' are same , the area of sector comes to be 72cm^2.

Length of AC = Length of BC.

Therefore, by 45-45-90 theorem, Angle A and angle B = 45°

If Angle A = 45° , area of circle of which AEF is a sector = Area of sector AEF × 8

= 72 × 8

= 576 cm^2

Answer : The area of the circle of which AEF is a sector is 576cm^2.