Question

please help me
please help me​

Answer 1

Answer:

$\frac{3x - 2}{2x + 3} = \frac{6x + 1}{4x + 5}$

$\scriptsize(3x - 2)(4x + 5) = (6x + 1)(2x + 3)$

$\scriptsize3x(4x + 5) - 2(4x + 5) = 6x(2x + 3) + 1(2x + 3)$

$\scriptsize12 {x}^{2} + 15x - 8x - 10 = 12 {x}^{2} + 18x + 2x + 3$

$\scriptsize12 {x}^{2} + 7x - 10 = 12 {x}^{2} + 20x + 3$

$\scriptsize12 {x}^{2} - 12 {x}^{2} - 10 - 3 = 20x - 7x$

$- 13 = 13x$

$\frac{ \cancel{- 13}}{ \cancel{13}} = x$

$- 1 = x$

$or \: \: \: x = - 1$

I hope it is helpful

Answer 2

Let's solve your equation step-by-step.

3x−2

2x+3

=

6x+1

4x+5

Step 1: Cross-multiply.

3x−2

2x+3

=

6x+1

4x+5

(3x−2)*(4x+5)=(6x+1)*(2x+3)

12x2+7x−10=12x2+20x+3

Step 2: Subtract 12x^2 from both sides.

12x2+7x−10−12x2=12x2+20x+3−12x2

7x−10=20x+3

Step 3: Subtract 20x from both sides.

7x−10−20x=20x+3−20x

−13x−10=3

Step 4: Add 10 to both sides.

−13x−10+10=3+10

−13x=13

Step 5: Divide both sides by -13.

−13x

−13

=

13

−13

x=−1

Answer:

x=−1