Question

please help me please help me because I am in hurry and I want to do my 14 and 15 number because today is my weekly test and cycle test in which have to score good marks to be a good student ​

Answer 1

Step-by-step explanation:

In question no. 14:-

angle ABC=90° ( Angle of a square is 90°)

angle CBE =60°(Angle in a equilateral triangle is 60°)

angle ABE= angle ABC + angle CBE

angle ABE=90°+60°

angle ABE=150°

In triangle ABE:-

AB=BE

angle BAE= angle BEA

BAE + BEA+ ABE = 180°

2BAE+150°=180°

2BAE=30°

BAE =15°

b) angle EAC

In triangle ADC:-

angle ADC = 90°

AD=DC

angle DAC=angle DCA

angle ADC + angle DAC + angle DCA=180°

90°+2DAC=180°

2DAC=90°

DAC=45°

NOW,

angle DAC+ angle EAC + angle BAE = 90° ( ANGLE DAB = 90° ,

angle of a square)

45°+angle EAC+15°=90°

angle EAC =90° - 60°

angle EAC = 30°

HOPE IT HELPS YOU IN YOUR TEST.

PLEASE MARK IT AS BRAINLIESTANSWER!

Answer 2

Step-by-step explanation:

In Euclidean geometry, a parallelogram is a simple (non-self-intersecting) quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure