Question

please help me please help me please help me please help me please help me​

Answer 1

Answer:

Let O be the origin on the line 1.

Let A be on the line such that OA=1.

Draw AB perpendicular to OA at A such that AB=1.

Then

$OB^{2}$=$OA^{2}$+$AB^{2}$=$1^{2}$+$1^{2}$=2 Thus OB=$\sqrt{2}$

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With O as centre and OB as radius draw an arc cutting the line at C.

Then OC=OB=$\sqrt{2}$

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Again draw CD prependicular to 1 such that CD=1.

Then  $OD^{2}$=$OC^{2}$+$CD^{2}$=2+1=3. Thus OD=$\sqrt{3}$

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Draw an arc with O as centre and OD as radius to cut 1 in E.

Then OE=OD=$\sqrt{3}$

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Draw EF prependicular to 1 at E such that EF = 2 and join OF. Now

$OF^{2}$=$OE^{2}$+$EF^{2}$=3+4=7.

Hence OF=$\sqrt{7}$  With O as centre and OF as radius, cut 1 at G.

Then OG=OF=$\sqrt{7}$

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Thus G represents $\sqrt{7}$ On the line 1.