Math, asked by puspalatasahoo207, 7 months ago

please help me please please please only 2 number​

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Answers

Answered by rishu1910
1

Answer:

let no. be x

2a^2-b^2+3a^2b-X=a^2+b^2+3ab^2-6

x= a^2-2b^2+3a^2b-3ab^2+6

Step-by-step explanation:

Answered by bighnes87
2

\huge\green{A}\orange{N}\red{S}\pink{W}{E}\blue{R}

2. Let the number be x

so,

2a²-b²+3a²b-x=a²+b²+3ab²-6

⇒-x=a²+b²+3ab²-6-(2a²-b²+3a²b)

⇒-x=a²+b²+3ab²-6-2a²+b²-3a²b

⇒ -x= -2a²+a²+b²+b²+3ab²-3a²b-6

⇒ -x= -a²+2b²+3ab²-3a²b-6

⇒x= -( -a²+2b²+3ab²-3a²b-6)

⇒x=a²-2b²-3ab²+3a²b+6

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