Math, asked by shree705, 1 year ago

please help me
please solve number 9 to11 please do in full process

Attachments:

Answers

Answered by VemugantiRahul
3
Hi there!
Here's the answer :

°•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°

(9)

Given,
l : m = (3/2) : (7/4)

=> l/m = (3×4)/(2×7)
=> l/m = 12/14
=> l/m = 6/7

m : n = (7/3) : (21/5)
=> m/n = (7×5)/(3×21)
=> m/n = 35/63
=> m/n = 5/9

(i) l/n = (l/m)×(m/n)
l/n = (6/7) × (5/9)
=> l/n = (6×5)/(7×9)
=> l/n = 30/45
=> l/n = 6/9
=> l/n = 2/3
•°• l:n = 2:3


(ii) l:m:n
l:m = 6:7
m:n= 5:9
=> l:m:n = [5×(7/5)] : [9×(7/5)]
=> l:m:n = 5 : (63/5)
=> l:m:n = 6:25:63


°•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°

(10)

Given,
B:C = 6:11
let B's share = 6x
and C's share = 11x

A's share = (3/5) × B's share
=> A's share = (3/5)× 6x

Sum of All shares = ₹1545
=> [(3/5)×6x] + 6x + 11x = ₹1545
=> (18x/5) + 6x + 11x = ₹1545
=> (18x+30x+11x)/5 = ₹1545
=> 103x/5 = ₹1545
=> x = ₹(1545×5)/103
=> x= ₹75

•°• B's share 6x = (6×₹75) = ₹450
C's share 11x = (11×₹75) = ₹825
A's share [(3/5)×6x] = [(3/5)×₹450] = ₹270


°•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°

(11)

Given,
Expenditures : Savings = 7:3
Let Expenditures = 7x
and Savings = 3x
As per data given,
7x = ₹6300
=> x = ₹(6300/7) = ₹900

•°• Savings 3x = (3×₹900) = ₹2700
& Expenditures 7x = (7×₹900) = ₹6300

Total Income = Expenditures + Savings
=> Total Income = ₹ (2700+6300) = ₹9000

•°• Total Income = ₹9000

°•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°

:)
©#£€®$
Hope it helps

VemugantiRahul: my pleasure
Answered by shawvishwa
0

Answer:

(9) 1》L:M=3/2:7/4 and M:N=7/3:21/5

L/M=3/2×4/7 and M/N=7/3×5/21

L/M=6/7 and M/N=5/9

L/M×M/N=6/7×5/9

L/N=10/21

L:N=10:21

(9) 2》L:M=3/2×4/7 and M:N=7/3×5/21

L:M=6/7 and M:N=5/9

LCM of m=7×5=35

L:M=6:7

L/M=6/7×5/5=30/35

M/N=5/9×7/7=35/63

L:M:N=30:35:63

10,11 mujhe bhi nahi pata acha apna naam bata sakti hai mera naam vishwa shaw hai

Similar questions