Question

please help me please solve these problems please
Number 7 and8 with full reason

Answer 1

Answer:

Step-by-step explanation:

Given:AD=BC and AD||BC

To Prove:AD=BC

Proof: In ABCD

AD=BC

AD||BC

In a quadrilateral if one pair of opposite side is equal and parallel then it is a parallelogram

Therefore

Quadrilateral ABCD is a parallelogram

So,AB=CD

Opposite side of a parallelogram are equal

(Hence Proved)

Q8

Given:<BAC=<BDC=90

AC=BD

To Prove:∆ ABC =~ ∆DCB

Proof :In ∆ABC and ∆DCB

<BAC=<BDC=90(given)

AC=BD(given)

BC=BC(common)

(Hence Proved)

Answer 2

Answer:

Step-by-step explanation:

Q7

AD = BC(given)

AC =AC(common)

Angle BCA = Angle CAD(alternate angles)

Triangle ABC is congruent to triangle ADC

AB = DC(corresponding parts of congruent triangles)

Q8

AC = BD(given)

BC = BC(given)

Angle A = Angle D(both equal to 90 degree)

Triangle ABC is congruent to triangle DBC