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Given :-
- AB = AC
- BE & CF are bisector of ∠B and ∠C respectively
To prove :-
- BE = CF
Solution :-
We use the concept of congruency to solve this problem.
Since BE and CF are bisectors of angle B and C, this implies that:-
➝ ∠ABE = ∠EBC
➝ ∠ACF = ∠BCF
Also AB = AC implies that :-
➝ ∠ B = ∠ C [ angle opposite to equal sides ]
➝ ∠ABE = ∠EBC = ∠ACF = ∠BCF
Now consider ∆ ABE and ∆ ACF :-
➝ ∠ A = ∠A [ Common in both triangles ]
➝ AB = AC [ Given ]
➝ ∠ ABE = ∠ ACF [ Proved above ]
Hence ∆ ABE is congruent to ∆ ACF
➝ BE = CF [ By C.P.C.T. ]
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can be proved by SAS criteria
as in triangle FBC and triangle EBC :-
FB=EC ( given )
Angle FBC =Angle ECB ( opposite angles of isoselous triangles are equal )
BC =CB ( common side )
thus , ️FBC is congurent to ️EBC by SAS .
hence , BE= CF
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