Math, asked by PoushyaMeghana, 8 months ago

please help me plz plzzzzzzzzzzzzz :(​

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Answers

Answered by sbtech
0

Answer:

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No. 7.

thala

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Answered by MortalDyanamo12
0

3

2

(4

0

+5

3x

)=9

29

9

view step

Multiply both sides of the equation by 2929.

29\times 3^{2}\left(4^{0}+5^{\left(3x\right)}\right)=9\times 29+9

29×3

2

(4

0

+5

(3x)

)=9×29+9

329

29\times 9\left(4^{0}+5^{\left(3x\right)}\right)=9\times 29+9

29×9(4

0

+5

(3x)

)=9×29+9

view step

299261

261\left(4^{0}+5^{\left(3x\right)}\right)=9\times 29+9

261(4

0

+5

(3x)

)=9×29+9

view step

401

261\left(1+5^{\left(3x\right)}\right)=9\times 29+9

261(1+5

(3x)

)=9×29+9

view step

2611+5^{\left(3x\right)}

261+261\times 5^{\left(3x\right)}=9\times 29+9

261+261×5

(3x)

=9×29+9

view step

929261

261+261\times 5^{\left(3x\right)}=261+9

261+261×5

(3x)

=261+9

view step

2619270

261+261\times 5^{\left(3x\right)}=270

261+261×5

(3x)

=270

view step

261\times 5^{\left(3x\right)}+261=270

261×5

(3x)

+261=270

view step

261

261\times 5^{\left(3x\right)}=9

261×5

(3x)

=9

view step

261

5^{\left(3x\right)}=\frac{1}{29}

5

(3x)

=

29

1

view step

\log(5^{\left(3x\right)})=\log(\frac{1}{29})

log(5

(3x)

)=log(

29

1

)

view step

3x\log(5)=\log(\frac{1}{29})

3xlog(5)=log(

29

1

)

view step

\log(5)\approx 0.698970004

3x=\frac{\log(\frac{1}{29})}{\log(5)}

3x=

log(5)

log(

29

1

)

view step

\frac{\log(a)}{\log(b)}=\log_{b}\left(a\right)

3x=\log_{5}\left(\frac{1}{29}\right)

3x=log

5

(

29

1

)

view step

3

x=-\frac{\log_{5}\left(29\right)}{3}

x=−

3

log

5

(29)

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