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nd 3 rd ....
3) 6+√2
we have to prove 6+√2 is irrational
let us assume the opposite,
i.e, 6+√2 is rational
Hence, 6+√2 is can be written in the form of a/b
where a nd b ( b ≠ 0 ) are co- prime ( no common factor other than 1)
Hence, 6+√2 = a/b
√2 = a/b -6
√2 = a-6b /b
√2= irritational
a/b-6 = rational
Here , a/b-6 is rational number...
but √5 is irrational
since, Rational ≠ irrational
This is contradiction....
our assumption is incorrect.....
hence 6+√2 is irrational...
hence proved.....
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