Question

please help me Q.no.23 . please ☆☆☆​

Answer 1

Answer:

Step-by-step explanation:

Given : AB = AC

            AD ⊥ BC  

To prove : AD is median

Proof : In ΔABD and ΔACD

                    ∠D = ∠D     ( each 90°  ∵ AD ⊥ BC)

                     AB = AC    ( given)

                     AD = AD    (common)

                  ∴ ΔABD ≅ACD   (RHS congruence)

               ⇒   BD = CD   (CPCT)

              ∴ D is the midpoint of BC

           Hence AD is median.

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