Question

please help me Q. no.24.​

Answer 1

Answer:

May be helpful if can reach your question please mark as brainlist....

Step-by-step explanation:

ABC is a right triangle,

In which \angle ACB = 90^{\circ}∠ACB=90

∘

Also, CD \perp ABCD⊥AB and DE \perp ABDE⊥AB

Where D is any point in AB and E is any point in CB.

To prove : CD^2 \times AC= AD \times AB \times DECD

2

×AC=AD×AB×DE

Proof:

In triangles, ACB and ADC,

\angle CAB\cong \angle DAC∠CAB≅∠DAC ( Reflexive)

\angle ACB\cong \angle ADC∠ACB≅∠ADC ( Right angles)

Thus, By AA similarity postulate,