please help me sir or mam. please give full answer.
Answers
Step-by-step explanation:
Given :-
(2/3)x²-(4/5)xy³-(2/3) and (5/6)x²-(4/5)+(7/10)xy³
and (2/9)x²-(14/15)xy³+(7/15)
To find :-
Subtract the sum of (2/3)x²-(4/5)xy³-(2/3) and (5/6)x²-(4/5)+(7/10)xy³ from (2/9)x²-(14/15)xy³+(7/15)
Solution:-
Given expressions are :
(2/3)x²-(4/5)xy³-(2/3) and (5/6)x²-(4/5)+(7/10)xy³
and (2/9)x²-(14/15)xy³+(7/15)
Sum of (2/3)x²-(4/5)xy³-(2/3) and (5/6)x²-(4/5)+(7/10)xy³
=>[ (2/3)x²-(4/5)xy³-(2/3)] +[ (5/6)x²-(4/5)+(7/10)xy³]
=> [(2/3)x²+(5/6)x²]+[(-4/5)xy³+(7/10)xy³]+[(-2/3)-(4/5)]
=> [(2/3)+(5/6)]x² + [ (-4/5)+(7/10)]xy³+[(-2/3)-(4/5)]
=> [(4+5)/6]x²+[(-8+7)/10]xy³+[(-10-12)/15]
=> (9/6)x²+(-1/10)xy³+(-22/15)
On Subtracting (9/6)x²+(-1/10)xy³+(-22/15) from (2/9)x²-(14/15)xy³+(7/15)
=> [(2/9)x²-(14/15)xy³+(7/15)]-[(9/6)x²+(-1/10)xy³+(-22/15)]
=>(2/9)x²-(14/15)xy³+(7/15)-(9/6)x²+(1/10)xy³+(22/15)]
=> [(2/9)-(9/6)]x²+[(-14/15)+(1/10)]xy³+[(7/15)+(22/15)]
=> [(4-27)/18]x²+[(-28+3)/30]xy³+[(7+22)/15]
=> (-23/18)x²+(-25/30)xy³+(29/15)
=> (-23/18) x² -(5/6)xy³ + 29/15
Answer:-
Answer for the given problem is
(-23/18 )x² -(5/6) xy³ + 29/15
Used formulae:-
Change the signs of the terms in the second expression when subtract the second expresion from the first expression.