please help me sir or mam. please give full answer and solve both of them
Answers
Step-by-step explanation:
Given :-
a)4a²+7a+9 , 10a²-12
b) 4x³-(2/3)x²y+5 , 8x³+(5/6)x²y+9
To find :-
Subtract first expression from the second expression?
Solution:-
a)
Given expressions are 4a²+7a+9 , 10a²-12
On Subtracting 4a²+7a+9 from 10a²-12 then
=>( 10a²-12) - (4a²+7a+9 )
=> 10a²-12 -4a²-7a-9
=> (10a²-4a²)-7a-(12+9)
=> (10-4)a²-7a-21
=> 6a²-7a-21
b)
Given expressions are
4x³-(2/3)x²y+5 , 8x³+(5/6)x²y+9
On Subtracting 4x³-(2/3)x²y+5 from 8x³+(5/6)x²y+9
=>[8x³+(5/6)x²y+9] -[4x³-(2/3)x²y+5]
=> 8x³+(5/6)x²y+9 -4x³+(2/3)x²y-5
=> (8x³-4x³) +(5/6 x²y+ 2/3x²y) +(9-5)
=> (8-4)x³+ [ (5/6)+(2/3)]x²y +4
=> 4x³ +(5+4)/6 x²y+4
=> 4x³+9/6 x²y+4
=> 4x³+3/2 x²y+4
Answer:-
a) 6a²-7a-21
b)4x³+3/2 x²y+4
Used formulae:-
Change the signs of the terms in the second expression when Subtracting the second expression from the first expression.