Question

Please,help me sistem or brother

Answer 1

Answer:

Step-by-step explanation:

7a). f(x) = 2 sin x

Domain: ( - ∞ , ∞ )

Range: [ - 2, 2 ]

Minimum of f(x) is (- 2) and reached at points ((2nπ - π/2) , - 2), n∈Z

Maximum of f(x) is 2 and reached at points ((π/2 + 2nπ) , 2), n∈Z

y-intersect at (0, 0) , x-intersect at (nπ, 0), n∈Z

7b). f(x) = - 3cos x

Domain: ( - ∞ , ∞ )

Range: [ - 3, 3 ]

Minimum of f(x) is (- 3) and reached at points (2nπ , - 3) , n∈Z

Maximum of f(x) is 2 and reached at points (π(1 + 2n) , 3), n∈Z

y-intersect at (0, - 3) , x-intersect at (π/2 + nπ, 0), n∈Z

7c). f(x) = tan x

Domain: R - {π/2+nπ}  

Range: ( - ∞ , ∞ )

Function does not have minimum or maximum

y-intersect at (0, 0) , x-intersect at (π/2 + nπ, 0), n∈Z

Discontinuous at x = π/2 + nπ , n∈Z

7d). NOW IS YOUR TURN, it's good for practice. The graph is attached.