Question

PLEASE HELP ME SLOVE THAT​

Answer 1

Step-by-step explanation:

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Answer 2

Solution :-

$\rightarrow\sf \: 3( \frac{2k + 1}{k + 1}) + \frac{7k + 3}{k + 1} - 9 = 0$

taking 9 to the RHS side and changing the sign,

$\rightarrow\sf \: 3( \frac{2k + 1}{k + 1}) + \frac{7k + 3}{k + 1} = 9$

multiply by 3 inside bracket now,

$\rightarrow\sf \: \frac{6k + 3}{k + 1} \: + \frac{7k + 3}{k + 1} = 9$

taking LCM of denominators now,

$\rightarrow\sf \: \frac{6k + 3 + 7k + 3}{k + 1} = 9 \\ \\\rightarrow\sf \: \frac{13k + 6}{k + 1} = 9 \\ \\ \bf \: cross - multiply \\ \\ \rightarrow\sf \: 13k + 6 = 9(k + 1) \\ \\ \rightarrow\sf \: 13k + 6 = 9k + 9 \\ \\ \rightarrow\sf \: 13k - 9k = 9 - 6 \\ \\ \rightarrow\sf \: 4k = 3 \\ \\ \rightarrow\boxed{\bf \: k = \frac{3}{4}}$

Hence, value of k will be (3/4) .

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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