Math, asked by anushkashah001, 9 months ago

Please help me solve​

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Answered by kuldeep20941
2

Answer:

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See The Attachment My Friend....

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Answered by AdorableMe
63

\displaystyle{\sf{\frac{b^2}{\sqrt{a^2+b^2}+a } }}\\\\\\\displaystyle{\sf{=\frac{b^2}{\sqrt{a^2+b^2}+a }*\frac{\sqrt{a^2+b^2}-a }{\sqrt{a^2+b^2}-a} }}\\\\\\\displaystyle{\sf{=\frac{b^2(\sqrt{a^2+b^2}-a) }{(\sqrt{a^2+b^2} )^2-(a)^2} }}\\\\\\\displaystyle{\sf{=\frac{b^2(\sqrt{a^2+b^2}-a )}{a^2+b^2-a^2} }}\\\\\\\displaystyle{\sf{=\frac{b^2(\sqrt{a^2+b^2}-a )}{b^2}}}\\\\\\

\boxed{\displaystyle{\sf{=\sqrt{a^2+b^2}-a }}}

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