Question

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Answer 1

Answer:

 In triangle ABD and triangle ACB

    AB = AC   [given each equal to 5cm]

    ∠ABD = ∠CBD   [BD bisects ∠ABC]

    BD = BD   [common in both triangles]

so, ΔABD ≅ΔCBD

      By SAS criteria

1.  AD = CD   [corresponding part of congurent triangle]

2. ∠DAB = ∠BCD   [corresponding part of congurent triangle]

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