Question

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Answer 1

Answer:

(c).tan∅

Step-by-step explanation:

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Answer 2

Question:

If sin²Ø + cos²Ø = 1, the value of sin³Ø + sinØ cos²Ø is

(a) sinØ (b) secØ (c) -tanØ

Answer:

a) sinØ

Step-by-step explanation:

→ sin³Ø + sinØ cos²Ø

We know that,

• sin²Ø + cos²Ø = 1
• cos²Ø = 1 - sin²Ø

→ sin³Ø + sinØ (1 - sin²Ø)

→ sin³Ø + sinØ - sin³Ø

→ sinØ

Therefore, the value of sin³Ø + sinØ cos²Ø is sinØ.

TRIGONOMETRY FORMULAS:

secØ = 1/cosØ, cosØ = 1/secØ

cosecØ = 1/sinØ, sinØ = 1/cosecØ

tanØ = sinØ/cosØ, cotØ = cosØ/sinØ

cotØ = 1/tanØ, tanØ = 1/cotØ

sin²Ø + cos²Ø = 1

tan²Ø + 1 = sec²Ø

1 + cot²Ø = cosec²Ø

sinØ = cos(90° - Ø)

cosØ = sin(90° - Ø)

tanØ = cot(90° - Ø)