Question

please help me solve me​

Answer 1

Step-by-step explanation:

In Δ ABO and ΔCBO

AB = BC (Given)

∠DAB = ∠ECB (Given)

BO = BO (Common)

∴ Δ ABO ≅ Δ CBO ( SAS Congruency rule)

Hence we can say that,

∠DAB = ∠ECB ( CPCT)

CPCT = Corresponding parts of congruent triangles

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