Question

please help me solve Q.13​

Answer 1

Step-by-step explanation:

answer Bhai Log ----/////////////////////////

Answer 2

Step-by-step explanation:

x + y + z = 0 ( given)

x^3 + y^3 + z^3 = 3 xyz

identity : x^3 + y^3 + z^3 - 3xyz = ( x+y+z) ( x^2 + y^2 + z^2 - xy - yz - zx)

LHS

x^3 + y^3 + z^3 - 3xyz

RHS

( x+y+z) ( x^2 + y^2 + z^2 - xy - yz - zx)

value of (x+y+z) is equal to 0

0 × ( x^2 + y^2 + z^2 - xy - yz - zx)

= 0

therefore

x^3 + y^3 + z^3 - 3xyz = 0

x^3 + y^3 + z^3 = 0 + 3xyz

x^3 + y^3 + z^3 = 3xyz

HOPE IT HELPS