Math, asked by girlsfriend, 2 months ago

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Answered by FFdevansh
4

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Let ∠1 = 2k and ∠2 = 3k, where k is some constant.

Now, ∠1 and ∠2 form a linear pair.

∴ ∠1 + ∠2 = 180º

⇒ 2k + 3k = 180º

⇒ 5k = 180º

⇒ k = 36º

∴ ∠1 = 2k = 2 × 36º = 72º

∠2 = 3k = 3 × 36º = 108º

Now,

∠3 = ∠1 = 72º (Vertically opposite angles)

∠4 = ∠2 = 108º (Vertically opposite angles)

It is given that, l || m and t is a transversal.

∴ ∠5 = ∠1 = 72º (Pair of corresponding angles)

∠6 = ∠2 = 108º (Pair of corresponding angles)

∠7 = ∠1 = 72º (Pair of alternate exterior angles)

∠8 = ∠2 = 108º (Pair of alternate exterior angles)

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