please help me solve the question
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Step-by-step explanation:
in the triangle x=2x+3
in the square x=3x/2+7
in the circle x=x-3
a) 2*∆6+[]3-O1
= 2(2*6+3)+(3*3/2+7)-(1-3)
= (2*15)+(9/2+7)-(-2)
= 30+23/2+2
= 32+23/2
= 87/2
b) 1/2*[]2+O8-3*∆0
= 1/2(3*2/2+7)+(8-3)-3(2*0+3)
= 1/2(3+7)+5-3(0+3)
= 1/2*10+5-9
= 5+5-9
= 1
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