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According to the question
angle A + B = 180 (corresponding angles)
angle A = CAP + PAB or
(angle bisector)
(angle bisector)
therefore
in triangle apc
pac + pca + apc = 180 (sum of angles of
triangle)
pac +pca = 90( from above)
therefore
90 + APC = 180
APC = 180 - 90
APC = 90°
hence proved
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angle A + B = 180 (corresponding angles)
angle A = CAP + PAB or
(angle bisector)
(angle bisector)
therefore
in triangle apc
pac + pca + apc = 180 (sum of angles of
triangle)
pac +pca = 90( from above)
therefore
90 + APC = 180
APC = 180 - 90
APC = 90°
hence proved
hey Friend...!!!
mark as brainliest if it is helpful
thank you
;-)
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