Question

please help me solve this 2 questions​

Answer 1

Answer:q1 30.5

Step-by-step explanation:

Answer 2

Answer: (question 1) Let n be the smaller of the two consecutive natural numbers. Then the larger number is n+1. 2n + 1 = 61 or 2n = 60 or n=30, making n+1 equal to 31.

1. (question 2) side 1 = 15m, s side 2 = 15m, side 3 = 25m, side 4 = 25m.
2. Explanation:
3. The perimeter of an object is the sum of all it's lengths. So in this problem, 80m = side1 + side2 + side3 + side4.
4. Now a rectangle has 2 sets of equal length sides.
5. So 80m = 2xSide1 + 2xSide2
6. And we are told that the length is 10m more than it's breadth.
7. So 80m = 2xSide1+(10+10) + 2xSide2
8. And we are told that the length is 10m more than it's breadth.
9. So 80m = 2xSide1+(10+10) + 2xSide2
10. So 80m = 2xS1+20 +2S2
11. 80 = 2x + 2y + 20
12. If it were a square, x + y would be the same
13. so
14. 60 = 4x side1
15. so side 1 = 60/4 = 15m
16. So side 1 = 15m, side 2 = 15m, side 3 = 15m+10m side 4 = 15+10m
17. So s1 = 15m, s2 = 15m, s3 = 25m, s4 = 25m.
18. Perimiter = 80m and the length of th e rectangle is 10m longer than the breadth

Step-by-step explanation:

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