Please help me solve this
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satyambundela:
answer is 6.
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Solution:
2x^2 - px + 4 = 0 when x=1
Therefore, 2 × 1^2 - p × 1 + 4 = 0
or 2 - p + 4 = 0
or p = 6
Check:
2x^2 - 6x + 4 = 0
dividing the above equation by 2, we get
x^2 - 3x + 2 = 0
(x - 2) (x - 1) = 0
Therefore, x = 2
& x = 1.
Hence, value of p should be 6.
2x^2 - px + 4 = 0 when x=1
Therefore, 2 × 1^2 - p × 1 + 4 = 0
or 2 - p + 4 = 0
or p = 6
Check:
2x^2 - 6x + 4 = 0
dividing the above equation by 2, we get
x^2 - 3x + 2 = 0
(x - 2) (x - 1) = 0
Therefore, x = 2
& x = 1.
Hence, value of p should be 6.
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Also check is necessary because whenever the question asked has "should be" instead of "is". As this question describes the possibility of the answer.
thx by the way
hey strawberry can i say something??????
yes
what u want to say?
hans math pagli pyaar ho jaayega
I'm not laughing
then laugh baby
stop
u r a idiot
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