Question

Please help me solve this equation (X-y-3z+2)² thanks

Answer 1

$(x−y−3z+2)^2$

$=(x+−y+−3z+2)(x+−y+−3z+2)$

$=(x)(x)+(x)(−y)+(x)(−3z)+(x)(2)+(−y)(x)+(−y)(−y)+(−y)(−3z)+(−y)(2)+(−3z)(x)+(−3z)(−y)+(−3z)(−3z)+(−3z)(2)+(2)(x)+(2)(−y)+(2)(−3z)+(2)(2)$

$=x^2−xy−3xz+2x−xy+y^2+3yz−2y−3xz+3yz+9z^2−6z+2x−2y−6z+4$

$=x^2−2xy−6xz+y^2+6yz+9z^2+4x−4y−12z+4$