Question

please help me solve this. I can't get the right answer. AND PLEASE DON'T SCAM

Answer 1

QUESTION:

A RECTANGULAR BLOCK OF METAL HAS WEIGHT 6.0N AND MEASURES 3.0 cm × 4.0 cm × 5.0 cm. WHAT IS THE SMALLEST PRESSURE THAT IT CAN EXERT WHILE RESTING ON A HORIZONTAL SURFACE?

ANSWER:

$P_2$ will have the lowest pressure of 3000 Pa

GIVEN:

l = 3.0 cm

b = 4.0 cm

h = 5.0 cm

F = 6 N

TO FIND:

Smallest pressure.

FORMULAE:

PRESSURE = FORCE/AREA

COVERSIONS USED:

1 cm² = 0.0001m²

EXPLANATION:

GIVEN METAL IS A CUBOID. HENCE IT HAS THREE AREAS.

l × b = 3 × 4 = 12 cm² = 0.0012 m²

b × h = 4 × 5 = 20 cm² = 0.002 m²

l × h = 5 × 3 = 15 cm = 0.0015 m²

Let

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$A_1$ be 0.0012 m²

$A_2$ be 0.002 m²

$A_3$ be 0.0015 m²

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$P_1$ = 6/0.0012

$P_1$ = 60000/12

$P_1$ = 10000/2

$P_1$ = 5000 N/m²

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$P_2$ = 6/0.002

$P_2$ = 6000/2

$P_2$ = 3000 N/m²

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$P_3$ = 6/0.0015

$P_3$ = 60000/15

$P_3$ = 4000 N/m²

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$P_2$ will have the lowest pressure of 3000 Pa

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EXTRA POINTS:

• We can also do this without calculation as Pressure inversly proportional to area the highest area will have the lowest pressure.
• Other unit of Pressure is pascal(Pa) which was given after by the name of a scientist called pascal.
• 1 N / m² = 1 Pa

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