please help me solve this problem.
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OPPOSITE angles of parallelogram are equal
(3x + 12)°=(2x + 52)°
or,3x-2x= 52-12
or,x = 40°
sum of all angles of parallelogram=360°
if 2 angles of parallelogram=40°
that means {360-(40+40)}=280°
as we know that opposite angles equal,
then 2angles =280°
each angle=280/2=140°
so,
1st angle=40
2nd angle=40
3rd =140
4th=140 and these are 4 angles of parallelogram
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Answer:
Angles are 81·6°, 98·4°, 81·6° and 98·4°
Step-by-step explanation: Since opposite angles of a ║gm are supplementary
∴ (3x+12)° + (2x+52)° = 180°
⇒ (3x + 12 + 2x + 52)° = 180°
⇒ (5x + 64)° = 180°
⇒ 5x = 180° - 64°
⇒ 5x = 116
⇒ x =
⇒ x = 23·2
Now,
put x = 23·2 in
(3x+12)° and (2x+52)°
⇒ 3(23·2) + 12 and 2(23·2) + 52
⇒ 81·6° and 98·4°
∴ Angles are 81·6°, 98·4°, 81·6° and 98·4°
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