Question

please help me solve this Q. no. 23​

Answer 1

Answer:

∠AEF>∠AFE

∠4 > ∠5

∴AF>AE

Step-by-step explanation:

In ΔABC,

AB=AC given

∴∠ACB=∠ABC

that means angle 2 and angle 3 are equal.

In ΔCDF,

∠ACB is an exterior angle.

∴∠ACB>∠DFC

that means angle 3 is grater than angle 6.

⇒∠ABC>∠DFC

so, angle 2 is grater than angle 6.

Also,

∠DFC=∠AFE  

∠6 = ∠5

⇒∠ABC>∠AFE

∠2 > ∠5

In ΔBDE,∠DEA is an exterior angle

∠DEA>∠ABC

∠4 > ∠ 2

⇒∠DEA>∠AFE  

∠4 > ∠5

In  ΔAEF,

∠AEF>∠AFE

∠4 > ∠5

∴AF>AE

Hence proved