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Answered by
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Answer:
Step-by-step explanation:
Answer
Remember
(x−α)(x−β)(x−γ)=x
3
−x
2
S
1
+xS
2
−S
3
Since a, b, c are the roots of
x
2
−px
2
+qx−r=0
s
1
=a+b+c=p=2sor s=p/2
s
2
=∑ab=q,s
3
=abc=r
△
2
=s(s−a)(s−b)(s−c)
=
2
P
(
2
P
−a)(
2
P
−b)(
2
P
−c)
=
2
P
[(
2
P
)
2
−(
2
P
)
2
s
1
+
2
P
s
2
−s
3
]
=
2
P
[
8
−p
3
+4pq−8r
]
∴△=
4
1
[p(4pq−p
3
−8r)]
1/2
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