Question

please help me solve this question​

Answer 1

Solution:-

To Simplify:-

$\frac{ {9}^{ \frac{2}{3} } }{ {9}^{ \frac{1}{5} } }$

Formula:-

$\frac{{a}^{c} }{ {a}^{r} } = {a}^{c - r}$

By the Problem:-

$\frac{ {9}^{ \frac{2}{3} } }{ {9}^{ \frac{1}{5} } } \\ \\ \implies {9}^{ \frac{2}{3} - \frac{1}{5} } \\ \\ \implies \: {9}^{ \frac{10 - 3}{15} } \\ \\ \implies \: {9}^{ \frac{7}{15} }$

Answer:-

$\\ \implies \boxed{ {9}^{ \frac{7}{15} }}$