Question

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Answer 1

Sin(50°-3/2α)=cos(3α-50°)

or, sin(50°-3/2α)=sin{90°-(3α-50°)}

or, 50°-3/2α=90°-3α+50°

or, -3/2α+3α=90°

or, (-3α+6α)/2=90°

or, 3α=90°×2

or, α=180°/3

or, α=60°

∴, tanαsecαsinα-cotαsinαcosα

=tan60°sec60°sin60°-cot60°sin60°co60°

=√3×2×√3/2-1/√3×√3/2×1/2

=3-1/4

=(12-1)/4

=11/4 Ans.

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