please help me solve this question I request you
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Given numbers are 81 and 237.
(1) 237 > 81
= > 237 = 81 * 2 + 75
(2)
= > 81 = 75 * 1 + 6
(3)
= > 75 = 6 * 12 + 3
(4)
= > 6 = 3 * 2 + 0.
Therefore the HCF of 81 and 237 = 3.
Now,
3 = 75 - 6 * 12
= > 75 - (81 - 75 * 1) * 12
= > 75 - 81 * 12 + 75 * 12
= > 75 * 13 - 81 * 12
= > (237 - 81 * 2) * 13 - 81 * 12
= > 237 * 13 - 81 * 26 - 81 * 12
= > 237 * 13 - 81 * 38
= > 237 * 13 + 81 * (-38).
Therefore the value of p = -38.
Hope this helps!
(1) 237 > 81
= > 237 = 81 * 2 + 75
(2)
= > 81 = 75 * 1 + 6
(3)
= > 75 = 6 * 12 + 3
(4)
= > 6 = 3 * 2 + 0.
Therefore the HCF of 81 and 237 = 3.
Now,
3 = 75 - 6 * 12
= > 75 - (81 - 75 * 1) * 12
= > 75 - 81 * 12 + 75 * 12
= > 75 * 13 - 81 * 12
= > (237 - 81 * 2) * 13 - 81 * 12
= > 237 * 13 - 81 * 26 - 81 * 12
= > 237 * 13 - 81 * 38
= > 237 * 13 + 81 * (-38).
Therefore the value of p = -38.
Hope this helps!
siddhartharao77:
:-)
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3
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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