Question

Please help me solve this thanks

Answer 1

Answer:

Given, sinA = √3/2, i.e., A = 60°

cosB = 1/2, i.e., B = 30°

Now, tan(A - B)

= tan(60° - 30°)

= tan30°

= 1/√3

Answer 2

sin60 = √3/2

A= 60 degree

cos45 = 1/√2

B = 45

substituting the values of A and B

tan 60 -. tan 45 / 1+ tan 60 tan 45

= √3- 1/ 1 +√3

now factorise them

=( √3 -1)/ (√3+1) *(√3-1/√3-1)

= 2- √3 is the value