Question

please help me solve this....
will mark the first and correct one as brainliest​

Answer 1

Problem 1.

Required solution is x = 10

Solution:

The given equation is

2x/3 + 1 = 7x/15 + 3

or, (2x + 3)/3 = (7x + 45)/15

or, 15 (2x + 3) = 3 (7x + 45)

or, 30x + 45 = 21x + 135

or, 30x - 21x = 135 - 45

or, 9x = 90

or, x = 10

Therefore the required solution is x = 10.

Reference: https://brainly.in/question/14890645

Problem 2.

2a² - 3b² - ab - 2bc + 3ac

Solution:

The given term is

(a + b) (2a - 3b + c) + (2ac - 3bc)

= a (2a - 3b + c) + b (2a - 3b + c) + (2ac - 3bc)

= 2a² - 3ab + ac + 2ab - 3b² + bc + 2ac - 3bc

= 2a² - 3b² - ab - 2bc + 3ac,

which is the required simplification.

More questions here:

- https://brainly.in/question/9690188

- https://brainly.in/question/9690468

Answer 2

1. Solve 2x/3 + 1 = 7x/15 + 3

(2x + 3)/3 = (7x + 45)/15

15(2x + 3) = 3(7x + 45)

30x + 45 = 21x + 135

30x - 21x = 135 - 45

9x = 90

∴ x = 10

Now, the left hand side is:

2x/3 + 1 = 20/3 + 1 = (20 + 3)/3 = 23/3

Now, the right hand side is:

7x/15 + 3 = 70/15 + 3 = (70 + 45)/15 = 115/15 = 23/3

∴ LHS = RHS

2. Simplify (a + b)(2a - 3b + c) + (2ac - 3bc)

1st expression: (a + b)(2a - 3b + c)

(a + b)(2a - 3b + c) = 2a² - 3ab + ac + 2ab - 3b² + bc

⇒ 2a² - ab + ac - 3b² + bc

2nd expression: (2ac - 3bc)

Now, on adding 1st and 2nd expression, we get,

2a² - ab + ac - 3b² + bc + 2ac - 3bc = 2a² - 3b² - ab + 3ac - 2bc