please help me solve (x+2) (x+4) (x+6) (x+8) = 105
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After factorising the last equation you will get the values of x
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prachithaman:
By which method should i factorise the last equation?
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(x+2)(x+4)(x+6)(x+8)=105
x(x+4)+2(x+4)(x+6)(x+8)=105
(x^2+4x+2x+8)x(x+8)+6(x+8)=105
(x^2+6x+8)(x^2+14x+48)=105
x^2(x^2+14x+48)+6x(x^2+14x+48)+8(x^2+14x+48)=105
x^4+20x^3+130x^2+400x+382=105
by factoring method,
105=105
LHS=RHS
HENCE PROVED
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