Question

please help me solving the question ​

Answer 1

Let theta =A.

(sinA-cosA+1)/(sinA+cosA-1)=1/(secA-tanA).

Take L.H.S.

=(sinA-cosA+1)/(sinA+cosA-1).

Dividing in Nr and Dr by cosA.

=(tanA-1+secA)/(tanA+1-secA).

=(tanA+secA-1)/(tanA-secA+1).

putting 1= sec^2A-tan^2A=(secA-tanA).

(secA+tanA). in Dr.

=(tanA+secA-1)/{-(secA-tanA)+(secA-tanA).(secA+tanA)}.

=(tanA+secA-1)/(secA-tanA).(-1+secA+tanA).

= 1/(secA-tanA).

Hence Proved.

(Note:- Nr and Dr is Numerator and Denominator).

Answer 2

Answer:

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