please help me solving this question
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2
Hey friend
Here is your answer
=sec50°sin40°+cos40°cosec50°
=cosec(90°-50°)sin40°+cos40°sec(90°-50°)
=cosec40°sin40°+cos40°sec40°
=(1/sin40°)×sin40°+cos40°×(1/cos40°)
=1+1
=2
Hope this helps you
Here is your answer
=sec50°sin40°+cos40°cosec50°
=cosec(90°-50°)sin40°+cos40°sec(90°-50°)
=cosec40°sin40°+cos40°sec40°
=(1/sin40°)×sin40°+cos40°×(1/cos40°)
=1+1
=2
Hope this helps you
marakroma18otss61:
cuteangel you are really cute...thank you very much....
Answered by
0
answer is 2 .............
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