Question

please help me someone​

Answer 1

Hello, Buddy!!

ɢɪᴠᴇɴ:-

• ABCD is a Parallelogram.
• ∠DAB = 85° & ∠DBC = 60°

ᴛᴏ ꜰɪɴᴅ:-

• ∠CDB
• ∠ABD

ʀᴇQᴜɪʀᴇᴅ ꜱᴏʟᴜᴛɪᴏɴ:-

WKT

Opposite Angles of a Parallelogram are Equal.

→ ∠DAB = ∠DCB

→ ∠DCB = 80°

In ∆DCB,

Let, ∠CDB be x

→ ∠DCB+∠DBC+∠CDB = 180° [Angle Sum Property of a Triangle]

→ 85°+60°+x = 180°

→ 145°+x = 180°

→ x = 180°-145°

→ x = 35°

• Value of ∠CDB ☞ 35°

As, AB||CD & DB as transversal

→ ∠CDB = ∠ABD [Alternative Interior Angles]

→ ∠ABD = 35°

• Value of ∠ABD ☞ 35°

@MrMonarque♡

Hope It Helps You ✌️

Answer 2

Step-by-step explanation:

Given :-

In the ABCD paralellogram < DAB = 85° and

< DBC = 60°

To find :-

Find the following :

i) < CDB

ii) < ABD

Solution :-

Given that

ABCD is a Parallelogram.

< DAB = 85°

< DBC = 60°

We know that

The adjacent angles are supplementary in a Parallelogram.

=> < DAB + < CDA = 180°

=> 85° + < CDA = 180°

=> < CDA = 180° - 85°

=> < CDA = 95°

Now,

AB || CD and BD is a transversal.

< CBD and < ADB are alternative interior angles

So they are equal.

=> < CBD = < ADB = 60°

Now,

We have ,

< CDA = 95°

=> < CDB + < ADB = 95°

=> 60° +< CDB = 95°

=> <CDB = 95°-60°

=> < CDB = 35°

We know that

The adjacent angles are supplementary in a Parallelogram.

=> < DAB + < ABC = 180°

=> < DAB + (< ABD + < DBC ) = 180°

=> 85° + < ABD + 60° = 180°

=> < ABD + 145° = 180°

=> < ABD = 180° -145°

=> < ABD = 35°

Answer :-

< CDB = 35°

< ADB = 35°

Note:-

< CDB and < ADB are the interior angles, So they are equal.

Used formulae:-

→ The adjacent angles are supplementary in a Parallelogram.

→ If two parallel lines Intersected by a transversal then alternative interior angles are equal.