Question

please help. me someone
please answer with explanation ​

Answer 1

$\sf \underline{ \bigstar \: Solution \: : }$

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$\sf : \implies \: \dfrac{a {}^{2} }{bc} + \dfrac{ {b}^{2} }{ca} + \dfrac{ {c}^{2} }{ab}$

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$\sf \: By \: taking \: the \: lcm \: of \: the \: denominator \: we \: get,$

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$\sf : \implies \: \dfrac{a {}^{3} + {b}^{3} + {c}^{3} }{abc}$

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$\sf \: We \: know \: that \: when \: a + b + c = 0, \: then \: {a}^{3} + {b}^{3} + {c}^{3} = 3abc$

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$\sf : \implies \: \cancel\dfrac{3abc}{abc}$

$\: \:$

$\sf \: Now,\: we've \: got \: our \: final \: answer$

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$\sf : \implies \: 3$

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$\sf \therefore \underline{Hence, \: \bold{ \dfrac{a {}^{2} }{bc} + \dfrac{ {b}^{2} }{ca} + \dfrac{ {c}^{2} }{ab}= 3} \: proved. }$