Please help me the last two sums fast
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Step-by-step explanation:
( x + y ) ² = x² + y² + 2xy
64 = x² + y² + 2 × 15 / 4
64 - 15 / 2 = x² + y ²
113/ 2 = x²+ y²
3 × 113 /2 = 3 ( x² + y ²)
339 / 3 = 3 ( x² + y² )
In the same way you find x - y
( x - y )² = x² + y² - 2xy
x- y = underroot ( x² + y² - 2xy )
substitute the values u get the answer
Hope you get it
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