Question

please help me this is my question ​

Answer 1

Answer:

100°

As line l || line n => m<POC = m<OCD = 110°

So m<ACD = 110°-30° = 80°

Also line m || line n => m<BAC = 180°- m<ACD = 180° - 80° = 100°

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Answer 2

Answer:

70

Step-by-step explanation:

angle POC = angle OCD

110°= 30° + angle ACD

Angel ACD = 110° - 30°

angel ACD = 80°

if we extend DC to S

then angle SCD = 180°

then angle SCO = 180-30°-80°

angle SCO = angle CAB

angle CAB = 70°