please help me this question is science chemistry and so fastly please answer
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(i) carboxylic acid is ethanoic acid(CH3COOH)
(ii)alcohol is ethanol (C2H5OH) which on oxidation with KMnO4 gives CH3COOH.
C2H5OH+2(O)------ CH3COOH+H20
(iii)substance X is ethyl ethanoate (CH3COOC2H5)
CH3COOH+C2H5OH------CH3COOC2H5+H20
hope it helpzzz ☺️
(ii)alcohol is ethanol (C2H5OH) which on oxidation with KMnO4 gives CH3COOH.
C2H5OH+2(O)------ CH3COOH+H20
(iii)substance X is ethyl ethanoate (CH3COOC2H5)
CH3COOH+C2H5OH------CH3COOC2H5+H20
hope it helpzzz ☺️
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