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This question says that what is the value of 'x' using Pythagoras theorem
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Hypotenuse2 = Perpendicular2 + Base2
c2 = a2 + b2
(37)^2=(12)^2+x^2
1369=144+x^2
1369-144=x^2
1225=x^2
X=√1225
X=11.1
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