Question

please help me this questions

Answer 1

ar rectangle = lb
                    = 20 x 14 (AB = 20cm BC = 14cm)
                    =280 cm^2......(1)
ar semicircle= $\pi r^{2}$
                    = 22/7 x 7 x 7 x 1/2 (BC= 14cm hence r=7cm)
                    = 11 x7 = 77 cm^2
ar remaining region = ar rectangle - ar semicircle
                                = 280 - 77
                                = 203 cm^2