Question

please help me to answer this ​

Answer 1

Step-by-step explanation:

3 red balls

3 green balls

For drawing 3 balls of different colour in second draw, he can  draw 1 or 2 ball of each colour in first draw. He can't draw 3 balls of same colour in first draw.

Case I- In first draw 1 red and 2 green ball picked up

          2 red 1 green 3 blue balls in bag 

chance that the 3 later balls being all of different colours =6C31C1∗2C1∗3C1=3/10

Answer 2

Answer:

red or blue

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