Question

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Answer 1

Question :

The equivalent capacitance for two capacitors connected in parallel is given by Ceq = C₁ + C₂. If C₁ = (10 ± 1) μF and C₂ = (20 ± 1) μF, then the equivalent capacitance in parallel can be written as

Answer :

• C₁ = (10 ± 1) μF
• C₂ = (20 ± 1) μF

★ Equivalent capacitance of the parallel connection :

→ C = C₁ + C₂

→ C = 10 + 20

→ C = 30 μF

★ Error in measurement :

In all mathematical operations, the errors are of addictive nature$.$

→ ∆C = ∆C₁ + ∆C₂

→ ∆C = 1 + 1

→ ∆C = 2 μF

∴ Eq. capacitance = (30 ± 2) μF

★ Additional Information :

• Every measurement is appropriate due to error in measurement.
• Least count errors are random errors but within a limited size; they occur with both random and systematic errors.